EX. US-13 Section Displacements for a Frame
Calculation of displacements at intermediate points of members of a plane frame is demonstrated in this example.
This problem is installed with the program by default to C:\Users\Public\Public Documents\STAAD.Pro 2023\Samples\Sample Models\US\US-13 Section Displacements for a Frame.STD when you install the program.
- L1 = 15 ft, L2 =20 ft
- P = 5.0 k
- w = 3.0 k/ft
The dashed line represents the deflected shape of the structure. The shape is generated on the basis of displacements at the ends plus several intermediate points of the members.
Actual input is shown in bold lettering followed by explanation.
STAAD PLANE TEST FOR SECTION DISPLACEMENT
Every input has to start with the term STAAD. The term PLANE signifies that the structure is a plane frame structure and the geometry is defined through X and Y axes.
UNIT KIP FEET
Defines the input units for the data that follows.
JOINT COORDINATES 1 0. 0. ; 2 0. 15. ; 3 20. 15. ; 4 20. 0.
Joint number followed by X and Y coordinates are provided above. Since this is a plane structure, the Z coordinates need not be provided.
MEMBER INCIDENCE 1 1 2 ; 2 2 3 ; 3 3 4
Defines the members by the joints to which they are connected.
MEMBER PROPERTY AMERICAN 1 3 TABLE ST W8X18 2 TABLE ST W12X26
Properties for all members are assigned from the American AISC steel table. The word ST stands for standard single section.
UNIT INCHES DEFINE MATERIAL START ISOTROPIC STEEL E 29000.0 POISSON 0.3 DENSITY 283e-006 ALPHA 6e-006 DAMP 0.03 TYPE STEEL STRENGTH FY 36 FU 58 RY 1.5 RT 1.2 END DEFINE MATERIAL CONSTANT MATERIAL STEEL ALL
The input units are changed from FT to INCH. The DEFINE MATERIAL command is used to specify material properties and the CONSTANT is used to assign the material to all members.
SUPPORT 1 FIXED ; 4 PINNED
A fixed support is specified at Joint 1 and a pinned support at Joint 4.
UNIT FT LOADING 1 DEAD + LIVE + WIND
Load case 1 is initiated followed by an optional title.
JOINT LOAD 2 FX 5.
Load 1 contains a joint load of 5 kips at node 2. FX indicates that the load is a force in the global X direction.
MEMBER LOAD 2 UNI GY -3.0
Load 1 contains a member load also. GY indicates that the load is in the global Y direction. The word UNI stands for uniformly distributed load.
PERFORM ANALYSIS
This command instructs the program to proceed with the analysis.
PRINT MEMBER FORCES
The above PRINT command is self-explanatory.
* * FOLLOWING PRINT COMMAND WILL PRINT * DISPLACEMENTS OF THE MEMBERS * CONSIDERING EVERY TWELFTH INTERMEDIATE * POINT (THAT IS TOTAL OF 13 POINTS). THESE * DISPLACEMENTS ARE MEASURED IN GLOBAL X * Y Z COORDINATE SYSTEM AND THE VALUES * ARE FROM ORIGINAL COORDINATES (UNDEFLECTED * POSITION) OF CORRESPONDING TWELFTH * POINTS. * * MAX LOCAL DISPLACEMENT IS ALSO PRINTED. * THE LOCATION OF MAXIMUM INTERMEDIATE * DISPLACEMENT IS DETERMINED. THIS VALUE IS * MEASURED FROM ABOVE LOCATION TO THE * STRAIGHT LINE JOINING START AND END * JOINTS OF THE DEFLECTED MEMBER. * PRINT SECTION DISPLACEMENT
Above PRINT command is explained in the comment lines above.
FINISH
This command terminates the STAAD run.
Input File
STAAD PLANE TEST FOR SECTION DISPLACEMENT
UNIT KIP FEET
JOINT COORDINATES
1 0. 0. ; 2 0. 15. ; 3 20. 15. ; 4 20. 0.
MEMBER INCIDENCE
1 1 2 ; 2 2 3 ; 3 3 4
MEMBER PROPERTY AMERICAN
1 3 TABLE ST W8X18
2 TABLE ST W12X26
UNIT INCHES
DEFINE MATERIAL START
ISOTROPIC STEEL
E 29000.0
POISSON 0.3
DENSITY 283e-006
ALPHA 6e-006
DAMP 0.03
TYPE STEEL
STRENGTH FY 36 FU 58 RY 1.5 RT 1.2
END DEFINE MATERIAL
CONSTANT
MATERIAL STEEL ALL
SUPPORT
1 FIXED ; 4 PINNED
UNIT FT
LOADING 1 DEAD + LIVE + WIND
JOINT LOAD
2 FX 5.
MEMBER LOAD
2 UNI GY -3.0
PERFORM ANALYSIS
PRINT MEMBER FORCES
*
* FOLLOWING PRINT COMMAMND WILL PRINT DISPLACEMENTS
* OF THE MEMBERS CONSIDERING EVERY TWELVETH INTERMEDIATE
* POINTS (THAT IS TOTAL 13 POINTS). THESE DISPLACEMENTS
* ARE MEASURED IN GLOBAL X Y Z COORDINATE SYSTEM AND
* THE VALUES ARE FROM ORIGINAL COORDINATES (THAT IS
* UNDEFLECTED) OF CORRESPONDING TWELVETH POINTS.
*
* MAX LOCAL DISPLACEMENT IS ALSO PRINTED. THE LOCATION
* OF THE MAXIMUM INTERMEDIATE DISPLACEMENT IS DETERMINED.
* THIS VALUE IS MEASURED FROM ABOVE LOCATION TO THE STRAIGHT
* LINE JOINING START AND END JOINTS OF THE DEFLECTED MEMBER.
*
PRINT SECTION DISPLACEMENT
FINISH
STAAD Output File
PAGE NO. 1 **************************************************** * * * STAAD.Pro 2023 * * Version 23.00.02.*** * * Proprietary Program of * * Bentley Systems, Inc. * * Date= DEC 15, 2023 * * Time= 15:59:49 * * * * Licensed to: Bentley Systems Inc * **************************************************** 1. STAAD PLANE TEST FOR SECTION DISPLACEMENT INPUT FILE: D:\Documentation\STAAD.Pro\_Automated_Py\output\2023-12-15\SPro_Output_Input_Files\Sample .. .STD 2. UNIT KIP FEET 3. JOINT COORDINATES 4. 1 0. 0. ; 2 0. 15. ; 3 20. 15. ; 4 20. 0. 5. MEMBER INCIDENCE 6. 1 1 2 ; 2 2 3 ; 3 3 4 7. MEMBER PROPERTY AMERICAN 8. 1 3 TABLE ST W8X18 9. 2 TABLE ST W12X26 10. UNIT INCHES 11. DEFINE MATERIAL START 12. ISOTROPIC STEEL 13. E 29000.0 14. POISSON 0.3 15. DENSITY 283E-006 16. ALPHA 6E-006 17. DAMP 0.03 18. TYPE STEEL 19. STRENGTH FY 36 FU 58 RY 1.5 RT 1.2 20. END DEFINE MATERIAL 21. CONSTANT 22. MATERIAL STEEL ALL 23. SUPPORT 24. 1 FIXED ; 4 PINNED 25. UNIT FT 26. LOADING 1 DEAD + LIVE + WIND 27. JOINT LOAD 28. 2 FX 5. 29. MEMBER LOAD 30. 2 UNI GY -3.0 31. PERFORM ANALYSIS TEST FOR SECTION DISPLACEMENT -- PAGE NO. 2 P R O B L E M S T A T I S T I C S ----------------------------------- NUMBER OF JOINTS 4 NUMBER OF MEMBERS 3 NUMBER OF PLATES 0 NUMBER OF SOLIDS 0 NUMBER OF SURFACES 0 NUMBER OF SUPPORTS 2 Using 64-bit analysis engine. SOLVER USED IS THE IN-CORE ADVANCED MATH SOLVER TOTAL PRIMARY LOAD CASES = 1, TOTAL DEGREES OF FREEDOM = 7 TOTAL LOAD COMBINATION CASES = 0 SO FAR. 32. PRINT MEMBER FORCES MEMBER FORCES TEST FOR SECTION DISPLACEMENT -- PAGE NO. 3 MEMBER END FORCES STRUCTURE TYPE = PLANE ----------------- ALL UNITS ARE -- KIP FEET (LOCAL ) MEMBER LOAD JT AXIAL SHEAR-Y SHEAR-Z TORSION MOM-Y MOM-Z 1 1 1 27.37 0.97 0.00 0.00 0.00 22.49 2 -27.37 -0.97 0.00 0.00 0.00 -7.88 2 1 2 4.03 27.37 0.00 0.00 0.00 7.88 3 -4.03 32.63 0.00 0.00 0.00 -60.39 3 1 3 32.63 4.03 0.00 0.00 0.00 60.39 4 -32.63 -4.03 0.00 0.00 0.00 0.00 ************** END OF LATEST ANALYSIS RESULT ************** 33. * 34. * FOLLOWING PRINT COMMAMND WILL PRINT DISPLACEMENTS 35. * OF THE MEMBERS CONSIDERING EVERY TWELVETH INTERMEDIATE 36. * POINTS (THAT IS TOTAL 13 POINTS). THESE DISPLACEMENTS 37. * ARE MEASURED IN GLOBAL X Y Z COORDINATE SYSTEM AND 38. * THE VALUES ARE FROM ORIGINAL COORDINATES (THAT IS 39. * UNDEFLECTED) OF CORRESPONDING TWELVETH POINTS. 40. * 41. * MAX LOCAL DISPLACEMENT IS ALSO PRINTED. THE LOCATION 42. * OF THE MAXIMUM INTERMEDIATE DISPLACEMENT IS DETERMINED. 43. * THIS VALUE IS MEASURED FROM ABOVE LOCATION TO THE STRAIGHT 44. * LINE JOINING START AND END JOINTS OF THE DEFLECTED MEMBER. 45. * 46. PRINT SECTION DISPLACEMENT SECTION DISPLACE TEST FOR SECTION DISPLACEMENT -- PAGE NO. 4 MEMBER SECTION DISPLACEMENTS ---------------------------- UNITS ARE - INCH MEMB LOAD GLOBAL X,Y,Z DISPL FROM START TO END JOINTS AT 1/12TH PTS 1 1 0.0000 0.0000 0.0000 0.0173 -0.0027 0.0000 0.0666 -0.0054 0.0000 0.1461 -0.0081 0.0000 0.2539 -0.0108 0.0000 0.3882 -0.0135 0.0000 0.5472 -0.0162 0.0000 0.7290 -0.0188 0.0000 0.9318 -0.0215 0.0000 1.1538 -0.0242 0.0000 1.3931 -0.0269 0.0000 1.6480 -0.0296 0.0000 1.9165 -0.0323 0.0000 MAX LOCAL DISP = 0.41112 AT 90.00 LOAD 1 L/DISP= 437 2 1 1.9165 -0.0323 0.0000 1.9162 -0.3903 0.0000 1.9158 -0.7221 0.0000 1.9154 -1.0010 0.0000 1.9151 -1.2067 0.0000 1.9147 -1.3260 0.0000 1.9144 -1.3523 0.0000 1.9140 -1.2856 0.0000 1.9136 -1.1331 0.0000 1.9133 -0.9082 0.0000 1.9129 -0.6316 0.0000 1.9125 -0.3303 0.0000 1.9122 -0.0385 0.0000 MAX LOCAL DISP = 1.31688 AT 120.00 LOAD 1 L/DISP= 182 3 1 1.9122 -0.0385 0.0000 2.0720 -0.0353 0.0000 2.1486 -0.0321 0.0000 2.1495 -0.0289 0.0000 2.0822 -0.0257 0.0000 1.9544 -0.0225 0.0000 1.7736 -0.0192 0.0000 1.5474 -0.0160 0.0000 1.2833 -0.0128 0.0000 0.9890 -0.0096 0.0000 0.6719 -0.0064 0.0000 0.3398 -0.0032 0.0000 0.0000 0.0000 0.0000 MAX LOCAL DISP = 0.83895 AT 75.00 LOAD 1 L/DISP= 214 ************ END OF SECT DISPL RESULTS *********** 47. FINISH TEST FOR SECTION DISPLACEMENT -- PAGE NO. 5 *********** END OF THE STAAD.Pro RUN *********** **** DATE= DEC 15,2023 TIME= 15:59:49 **** ************************************************************ * For technical assistance on STAAD.Pro, please visit * * http://www.bentley.com/en/support/ * * * * Details about additional assistance from * * Bentley and Partners can be found at program menu * * Help->Technical Support * * * * Copyright (c) Bentley Systems, Inc. * * http://www.bentley.com * ************************************************************